#Mesh Analysis
Leverage the linear characteristics of the elements to get equations that are linear combinations of the solutions obtained.
- Identify meshes in the circuit and assign then a mesh current (unknowns).
- Apply KVL as many times as unknowns are.
- Once the system of eq.s is solved, the net current in each branch will be the sum of mesh currents flowing through that branch.
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hello youssefffffffffffffffffffffffff Draw the mesh current you’re considering in exams. Not real currents. ![[Screenshot 2024-02-29 at 13.21.00.png]]
Voltage gain: negative. Voltage drop, positive. Have to declare your direction of positive for each mesh.
$$ \text{(mesh1) }I_1R_3 + (I_1-I_3)R_4 - V_a + (I_1 - I_2) R_2 = 0 $$ $$ \text{(mesh2) }I_2R_1+(I_2-I_1)R_2+V_a+(I_2-I_3)R_5=0 $$ $$ \text{(mesh3) }(I_3-I_2)R_5+(I_3-I_1)R_4+I_3R_6=0 $$The current flowing through $R_2$ would be $I_1-I_2$
- The number of independent equations satisfy
meshes = branches - nodes + 1
plus to minus (voltage drop) therefore add minus to plus (voltage gain) therefore subtract